Warriors star Stephen Curry has been named the NBA’s Teammate of the Year for the 2024/25 season, the league announced today (via Twitter).
The Twyman-Stokes Teammate of the Year award “recognizes the player deemed the best teammate based on selfless play, leadership as a mentor and role model to other NBA players, and commitment to his team,” per the NBA.
The award isn’t voted on by media members. A panel of league executives select the 12 finalists (six from each conference) for the award, while current players vote on the winner. Players receive 10 points for a first place vote, seven for second, five for third, three for fourth, and one point for fifth place.
Curry just narrowly won this season’s vote ahead of Rockets center Steven Adams.
Here are this season’s full voting results, according to the NBA, with the player’s point total noted in parentheses:
- Stephen Curry, Warriors (1,257)
- Steven Adams, Rockets (1,237)
- Jalen Brunson, Knicks (925)
- DeAndre Jordan, Nuggets (897)
- Nicolas Batum, Clippers (868)
- Donovan Mitchell, Cavaliers (850)
- Al Horford, Celtics (834)
- James Johnson, Pacers (751)
- Jaylin Williams, Thunder (690)
- Brook Lopez, Bucks (657)
- Tobias Harris, Pistons (648)
- Jaren Jackson Jr., Grizzlies (552)
It’s the first Teammate of the Year award for Curry, though it’s the seventh time in a row that a point guard has earned the honor.
The award, which was introduced in ’12/13, had gone to either Mike Conley (2019 and 2024) or Jrue Holiday (2020, 2022, and 2023) in five of the past six seasons, with Damian Lillard claiming it in 2021.
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