The Milwaukee Bucks have locked up Jrue Holiday. Jeff Hanisch-USA TODAY Sports

Jrue Holiday, Bucks agree to four-year extension worth up to $160 million

By Erin Walsh | Last updated 4/4/21

The Milwaukee Bucks have locked up Jrue Holiday.

The guard's agent, Jason Glushon, told The Athletic's Shams Charania that Holiday agreed to a four-year extension worth up to $160 million on Sunday.

The deal ties Holiday to the Bucks through the 2024-25 season.

Since his trade to the Bucks in November, Holiday better familiarized himself with the roster, coaching staff and front office, and wanted to commit to the franchise and years of competing for championship in Milwaukee. https://t.co/CFisFXNFB9 https://t.co/4rbtLGPzTo
— Shams Charania (@ShamsCharania) April 4, 2021

The Bucks acquired Jrue Holiday from the New Orleans Pelicans in November 2020 in exchange for George Hill, Eric Bledsoe, three first-round picks and two pick swaps.

Holiday has been a solid addition to the Bucks this season, averaging 17 points, 4.6 rebounds and 5.4 assists per game while shooting 50.9% from the field and 39% from deep. His defensive prowess on the wing is also part of the reason why Milwaukee traded for him as he's an upgrade over both Hill and Bledsoe.

The 30-year-old was set to become a free agent after the 2021-22 season, but his maximum extension means he'll remain in Milwaukee for the long haul.

The Bucks now have Holiday, Giannis Antetokounmpo and Khris Middleton locked up long-term. Antetokounmpo agreed to a five-year, $228 million extension with the Bucks in December, and Middleton agreed to a five-year, $178 million deal in June 2019.

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