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Seahawks to make Jamal Adams NFL's top-paid safety?
Seahawks safety Jamal Adams appears to be set to become the highest-paid safety in the league. Joe Nicholson-USA TODAY Sports

Seahawks willing to make Jamal Adams NFL's highest-paid safety?

The Seattle Seahawks appear prepared to throw the bag at Jamal Adams. 

According to NFL Network's Mike Garafolo, the Seahawks are willing to make Adams the highest-paid safety in the NFL. 

"They're in the right realm already, so I believe at some point before the start of the season, this gets done between the Seahawks and Jamal Adams because they're where they should be as far as making him the highest-paid safety," Garafolo said (h/t NFL.com's Kevin Patra).

Adams will play the 2021 season on his fifth-year option, which carries a $9.86 million salary. 

Justin Simmons is currently the NFL's highest-paid safety after signing a four-year, $61 million deal with the Denver Broncos. Arizona Cardinals star Budda Baker also makes $14.75 million per season. 

According to Garafolo, Adams might view himself closer to being a Fred Warner than a Simmons. Warner recently signed a five-year, $95 million extension ($19 million AAV) with the San Francisco 49ers. 

However, according to NFL Media, the Seahawks would like to keep Bobby Wagner as their highest-paid defensive player at $18 million a year.

Adams, 25, recorded a career-high 9.5 sacks, three pass breakups, one forced fumble, 83 tackles, 11 tackles for a loss and 14 quarterback hits in 12 games last season. It was his first campaign with the Seahawks after three seasons with the New York Jets

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